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Test the derivability at a point.
if f(x)={(2-x,for1≤x≤2)(x,for0
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this is much easier than it seems. take the derivative and get two expression \[f'(x) = \left\{\begin{array}{rcc} 1 & \text{if} & 0<x<1 \\ -1& \text{if} & 1<x<2 \end{array} \right. \] and since they do not agree at 1, there the derivative does not exist there
Also sketching a graph will help you see what's going on. Derivatives don't exist where the graph has 'corners', such as this one does.
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