The width of a rectangle is
(3x − 1)
cm. The length of the rectangle is twice the width. Find the area of the rectangle in terms of the variable x.

Question

lilg132 · Answer

2(3x-1) = (6x - 2)

(6x - 2) (3x - 1) = Area

anonymous · Answer

The area of a rectangle is the product of the width and the length. You already have the width (3x - 1). You know the length is twice this. How would you write the length?

anonymous · Answer

2(3x-1)^2

anonymous · Answer

That's a perfect answer as far as I'm concerned. Well done!

anonymous · Answer

$$2(3x-1)(3x-1) = 2(3x-1)^2$$The answers are equally valid without some kind of condition in the question.

lilg132 · Answer

wouldnt that mean

(6x - 2)^2 ?

the same as

(6x - 2) (6x - 2)

anonymous · Answer

Conventionally, the square would only apply to the bracket, not the two. If you wanted the 2 to be squared, you would normally write:
$$2^2(3x-1)^2$$or$$(2(3x-1))^2$$

lilg132 · Answer

ok i get itt thanks