Question

x^(2x) F'=

Answer 1

so it unclear to me what F is?

Answer 2

is it that junk before F'=?

Answer 3

i think its derivative of x^(2x)

Answer 4

\[F=x^{2x}\]
Take natural log of both sides
\[\ln(F)=\ln[x^{2x}]\]
\[\ln(F)=2x \ln(x)\]
Now differentiate both sides

Answer 5

thats cool, never did quite learn those

Answer 6

\[\frac{F'}{F}=2[ 1 \cdot \ln(x)+x \cdot \frac{1}{x}]\]

Answer 7

to solve for F' just multiply F on both sides

Answer 8

replace F with x^(2x)