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Let L={a,b,c,d,e,f}, P(L) is power set of L and ≤ is order relation on P(L) defined as: if r and t are relations, then r≤t iff every block in r is subset of some block in t. Show that lattice (P(L),≤) is not modular.
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What's the definition of modular here?
wait a second
lattice (L,∨,∧) is modular if a ≤ c implies a ∨ (b ∧ c) = (a ∨ b) ∧ c.
I know to draw Hasse diagram, but I don't know what t do after. Maybe to try to find N5?
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can u check this: let r2={{a,b}, {c}, {d}, {e}, {f}} r3={{c,d,e}, {a}, {b}, {f}} r4={{a,b,c,d}, {e}, {f}} r5={{a,b,c,d,f}, {e}} r6={{a,b,c,d,e,f}} is |dw:1323201799967:dw| N5 (penthagon) ?
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