Question

Assume that the mean wait time spent by women in a restroom line at a sporting event is 6.3 minutes with a standard deviation of 1.5 minutes. For this distribution, find a raw score that corresponds to a z-score of 1.8.

Answer 1

\[z= (xbar - \mu)/\sigma\]
You have \[\mu=6.3 \min\], \[\sigma=1.5 \min\] and z=1.8
All you have to do is solve for xbar \[xbar= z \sigma+\mu\]
xbar=9