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Mathematics 23 Online
OpenStudy (anonymous):

Check if my answer is right?

OpenStudy (anonymous):

here it is

myininaya (myininaya):

\[\sum_{i=12}^{25}(-5+13i)=-5\sum_{i=12}^{25}1+13\sum_{i=12}^{25}i\] ------------------------------------------ Think: \[\sum_{i=k}^{n}1=1(n-k+1)=n-k+1\] \[\sum_{i=1}^{25}i=\sum_{i=1}^{11}i+\sum_{i=12}^{25}i=\frac{25(25+1)}{2}=325\] but \[\sum_{i=1}^{11}i=\frac{11(11+1)}{2}=66\] so we have \[66+\sum_{i=12}^{25}i=325\] =>\[\sum_{i=12}^{25}i=325-66=259\] -------------------------------------------- so we have \[-5\sum_{i=12}^{25}1+13\sum_{i=12}^{25}i\] \[-5(25-12+1)+13(259)=3297\]

OpenStudy (anonymous):

Wow, thank you, you deserve more than just 1 medal for this :O that was a lot for you to put. Thank you

myininaya (myininaya):

lol i didn't want to post something that wasn't readable

OpenStudy (anonymous):

Haha well this was very helpful, I greatly thank you :)

myininaya (myininaya):

Thanks :)

OpenStudy (anonymous):

No problem :)

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