An object moves in a straight line so that its velocity after t seconds is v(t). Determine the displacement and distance traveled by the object on the given time interval. v(t)=3radical(t) - t on [0,36]...??

Question

anonymous · Answer

displacement $$s = \int\limits_{0}^{36} v(t)dt = 2t^{3/2} -  0.5 t^2$$
from 0 to 36

anonymous · Answer

and that is 2(36 ^ (3/2)) - 0.5(36^2) - 0 = -216

anonymous · Answer

This means it has effectively moved in the opposite direction because its velocity in the last part is negative. (It starts going forward, then goes back and ends up at -216)