Question

solve the following system of equations with steps shown:
F - 9/16FL - 3/4F1 - F2
F - 3/4FL - F1 + F2
F - FL + F1 + 3/4F2

Answer 1

plz dear god help me

Answer 2

i do not remember how to do this stuff

Answer 3

lol

Answer 4

i know F = 241..that's given

Answer 5

i have to solve for FL F1 AND F2

Answer 6

- 9/16FL - 3/4F1 - F2 =-241
- 3/4FL - F1 + F2 =-241
- FL + F1 + 3/4F2=-241

Answer 7

just do matrix

A x= B

x= A^-1 B

Answer 8

i don't know how to do matrix

Answer 9

i learned really basic stuff with system of equations..so this stuff is above my head

Answer 10

oh, I see,

Answer 11

you got 3 equation, let's reduce it

- 9/16FL - 3/4F1 - F2 =-241
- 3/4FL - F1 + F2 =-241
- FL + F1 + 3/4F2=-241



F1=( -241 +FL- 3/4 F2)


plug in that everytime you see F1
- 9/16FL - 3/4F1 - F2 =-241
- 3/4FL - F1 + F2 =-241


- 9/16FL - 3/4( -241 +FL- 3/4 F2) - F2 =-241
- 3/4FL - ( -241 +FL- 3/4 F2) + F2 =-241

Answer 12

now you got two by two equation

Answer 13

umm...if i give you a dollar will u do the rest? lol

Answer 14

I can give you answer, fine?

Answer 15

yea..that'd be a great help

Answer 16

i just need to write down the steps to it

Answer 17

hold on , you variable names don't help

Answer 18

not sure if this helps...but the answers should come close to FL = 5F/3, F1=F/2, F2 = F/3

Answer 19

was the answer to a similar problem we had with different numbers...i couldn't solve that one either

Answer 20

\[FL\to \frac{9 F}{7},F1\to \frac{5 F}{28},F2\to \frac{F}{7}\]

Answer 21

so so cool...can u show me the steps to get that?

Answer 22

yep, but I will tell you method called Inverse Soloution

1) Write you system as matrix
I send number to other sides
\[\left(
\begin{array}{ccc}
-\frac{9}{16} & -\frac{3}{4} & -1 \\
-\frac{3}{4} & -1 & 1 \\
-1 & 1 & \frac{3}{4}
\end{array}
\right).\left(
\begin{array}{c}
\text{FL} \\
\text{F1} \\
\text{F2}
\end{array}
\right)=\left(
\begin{array}{c}
-241 \\
-241 \\
-241
\end{array}
\right)\]

A x = B


we want to find x, so we multiply inverse of A to both side , leaving only x on left side

x= A^-1 B

A^-1=\[\left(
\begin{array}{ccc}
-\frac{4}{7} & -\frac{1}{7} & -\frac{4}{7} \\
-\frac{1}{7} & -\frac{13}{28} & \frac{3}{7} \\
-\frac{4}{7} & \frac{3}{7} & 0
\end{array}
\right)\]

\[\left(
\begin{array}{c}
\text{FL} \\
\text{F1} \\
\text{F2}
\end{array}
\right)=\left(
\begin{array}{ccc}
-\frac{4}{7} & -\frac{1}{7} & -\frac{4}{7} \\
-\frac{1}{7} & -\frac{13}{28} & \frac{3}{7} \\
-\frac{4}{7} & \frac{3}{7} & 0
\end{array}
\right).\left(
\begin{array}{c}
-241 \\
-241 \\
-241
\end{array}
\right)\]

Answer 23

and that's it?

Answer 24

when we multiply these two matrix we should get our answer

Answer 25

thank you so very much...i owe you huge

Answer 26

I assume this is for your science class?

Answer 27

physics of meteorology yes

Answer 28

yeah,you would use matrix for solving equations in application

Answer 29

let me show you wolfram alpha way.
note I changed you variables to a,b,c
http://www.wolframalpha.com/input/?i=Solve%5B%7BF%20-%209%2F16%20a%20-%203%2F4%20b%20-%20c%20%3D%3D%200%2C%20F%20-%203%2F4%20a%20-%20b%20%2B%20c%20%3D%3D%200%2C%20%20%20%20F%20-%20a%20%2B%20b%20%2B%203%2F4%20c%20%3D%3D%200%7D%2C%20%7Ba%2C%20b%2C%20c%7D%5D&t=crmtb01

Answer 30

i starred that

Answer 31

you started that?

Answer 32

no...i starred it..as in saved it for future reference

Answer 33

oh yeah, if you have graphing calculator (Like TI-83,84) you can also do it there