someone help please!!!
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\[\int\limits_{}^{}(5e^x + (1/x))dx\] \[\int\limits_{}^{}5e^x dx + \int\limits_{}^{}(1/x)dx\] \[5e^x + \ln(x)\]
thats what i thought!! thank you Jpomer325!
can you help me with one more?
there would also be an unknown constant added since there are no limits of integration \[5e^x+\ln(x)+C\]
yeah whats up
its a word problem! be patient!
go ahead
The management of an oil company estimates that oil will be pumped at a rate given by R(t)= (55/square root t + 8) in thousands of barrels per year. How many barrels will be produced the first 9 years? (use fundamental theorem)
haha thats funny i'm in petroleum engineering. anyway... \[R(t)= ((55/\sqrt{t})+ 8)\] You can rewrite this as: \[R(t) = 55t^{-1/2} + 8\] Now you take the integral: \[\int\limits_{0}^{9} R(t) = \int\limits_{0}^{9}55t^{-1/2} + 8\] \[\int\limits_{0}^{9}55t^{-1/2}dx + \int\limits_{}^{}8dx\] \[110x^{1/2}+8x\] Plug in 9 for x: \[110(9)^{1/2}+8(9)=402\] So your final answer is: 402 thousand barrels
We have a pre test that we are working on and that isn't one of our options....our choices are 113 or 36 or 454 or 142
hmm let me check my work one sec
Is the initial equation this: \[R(t)=55/\sqrt{t+8}\] or what I originally typed out?
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