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Mathematics 10 Online
OpenStudy (anonymous):

someone help please!!!

OpenStudy (anonymous):

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OpenStudy (anonymous):

\[\int\limits_{}^{}(5e^x + (1/x))dx\] \[\int\limits_{}^{}5e^x dx + \int\limits_{}^{}(1/x)dx\] \[5e^x + \ln(x)\]

OpenStudy (anonymous):

thats what i thought!! thank you Jpomer325!

OpenStudy (anonymous):

can you help me with one more?

OpenStudy (anonymous):

there would also be an unknown constant added since there are no limits of integration \[5e^x+\ln(x)+C\]

OpenStudy (anonymous):

yeah whats up

OpenStudy (anonymous):

its a word problem! be patient!

OpenStudy (anonymous):

go ahead

OpenStudy (anonymous):

The management of an oil company estimates that oil will be pumped at a rate given by R(t)= (55/square root t + 8) in thousands of barrels per year. How many barrels will be produced the first 9 years? (use fundamental theorem)

OpenStudy (anonymous):

haha thats funny i'm in petroleum engineering. anyway... \[R(t)= ((55/\sqrt{t})+ 8)\] You can rewrite this as: \[R(t) = 55t^{-1/2} + 8\] Now you take the integral: \[\int\limits_{0}^{9} R(t) = \int\limits_{0}^{9}55t^{-1/2} + 8\] \[\int\limits_{0}^{9}55t^{-1/2}dx + \int\limits_{}^{}8dx\] \[110x^{1/2}+8x\] Plug in 9 for x: \[110(9)^{1/2}+8(9)=402\] So your final answer is: 402 thousand barrels

OpenStudy (anonymous):

We have a pre test that we are working on and that isn't one of our options....our choices are 113 or 36 or 454 or 142

OpenStudy (anonymous):

hmm let me check my work one sec

OpenStudy (anonymous):

Is the initial equation this: \[R(t)=55/\sqrt{t+8}\] or what I originally typed out?

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