Question

Use the substitution formula to evaluate the indefinite integral. See attachment.

Answer 1

it gives you the solution
put
\[u=4-\sin(\frac{t}{2}),du=-\frac{1}{2}\cos(\frac{t}{2})dt\]
\[-2du=\cos(\frac{t}{2})dt\] and you get
\[-2\int u^2du\]

Answer 2

u=4-sin(t/2), then du will be -2[cos(t/2)]dt, you will then have
\[-2\int\limits_{}^{} u^2 du\]
Which comes out to -2u^3/3 +C]

Answer 3

Cool beans, just what I had. Thanks guys. :)