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Mathematics 22 Online
OpenStudy (anonymous):

SOmeone thats good at precalc please helpp

OpenStudy (anonymous):

hit me

OpenStudy (anonymous):

are you smart?LOL

OpenStudy (anonymous):

i would think so

OpenStudy (anonymous):

The inlation rate in the united states increased by approximately 2.78% per year from 2000 to 2007. What is the overall percent increase during the time period? use 8 years for your t value

OpenStudy (anonymous):

inflation*

OpenStudy (anonymous):

alright well you would use the future value equation: FV=PV*(1+rate)^time Taking an easy value for Present Value of 100 you would get: FV=(100)*(1+.0278)^8=124.53 Now to get the overall percent increase we do this: (FV-PV)/PV = (124.53-100)/100 = 0.2453*100= 24.53% So your answer is 24.53%.

OpenStudy (anonymous):

Basically i found how much $100 would be worth after 8 years of 2.78% inflation and then found out the percent by which that value had increased from $100.

OpenStudy (anonymous):

make sense?

OpenStudy (anonymous):

yes, thank you. i thought it hadto be exponentialthough, cause thats what were studdying

OpenStudy (anonymous):

it is exponential: FV=PV*(1+rate)^time where time is the exponent

OpenStudy (anonymous):

oh okay, can i ask another one?

OpenStudy (anonymous):

\[FV=PV*(1+rate)^{time}\]

OpenStudy (anonymous):

yeah shoot

OpenStudy (anonymous):

the oldest living trees in the world are the cristlecone pines in the white mountains. 4000 "growth rings" have been counted in the trunk of one of these, meaning theinner most ring is 4000 years old, what percent of the original carbon 14 you expect to find in the oldest ring of this tree?

OpenStudy (anonymous):

does it give you the half life of carbon-14? if not i can just look it up

OpenStudy (anonymous):

im pretty sure its 5730, just remembering from scinece class

OpenStudy (anonymous):

yeah thats right, alright let me type out the answer, one sec...

OpenStudy (anonymous):

The half life equation looks like this: \[N_f=N_0(1/2)^{t/h}\] where Nf is final amount of the material, No is the initial amount of material, t is the time elapsed, and h is the half life of the material. So again, for sake of ease, we'll use 100 grams as the initial amount of carbon, and we plug in our other values in to get the final amount: \[N_f=(100)(1/2)^{4000/5730}=61.64\] So if 61.64 grams is left out of the initial 100 grams, the percent left would be: 61.64%

OpenStudy (anonymous):

thats wierd we dont use those equations lol

OpenStudy (anonymous):

Well they're pretty much all the same, and they're all exponential. It's just the rate of growth or decay to the power of the time elapsed all multiplied by the initial amount. Compare the future value equation and the half-life equation and you'll see the similarity.

OpenStudy (anonymous):

oh okay(:ugh i have more, but theres soo much to type:(

OpenStudy (anonymous):

you could just give me the short version, like just the numbers and a summary

OpenStudy (anonymous):

pressure of air in earths atmosphere decreases exponentially with altitude. pressure at sea level is about 14.7 pounds per inch and the pressure at 2000 ft is approximately 13.5 write an exponential model for pressure of altitude,

OpenStudy (anonymous):

alright one sec ill type it out

OpenStudy (anonymous):

omg, youre going to universitly of texis?! i want to go there!!! ahah

OpenStudy (anonymous):

haha yeah its a great school and austin is an awesome city

OpenStudy (anonymous):

Yeah im just not smart enough for that pellet.haha

OpenStudy (anonymous):

pellet* lol

OpenStudy (anonymous):

wtf, S H I T

OpenStudy (anonymous):

hahaha this corrects too?! :o

OpenStudy (anonymous):

Alright so the general form of an exponential modeling equation is: \[y=a*b^x\] where a and b are coefficients that we'll solve for with the values given. Changing it so it is specific to our problem I'll write it as: \[Pressure=a*b^{Altitude}\] The problem says that at sea level (Altitude=0) the Pressure=14.7: \[14.7=a*b^{0}\] Since b^0=1, we get: \[14.7=a\] The problem also says that at Altitude=2000, Pressure=13.5: \[13.5=14.7*b^{2000}\] Solving for b, we get: \[0.9184=b^{2000} \rightarrow b=0.9999574 \] So the final equation is: \[Pressure=14.7*(0.9999574)^{Altitude}\]

OpenStudy (anonymous):

haha no i think you could get in. what major do you wanna go into?

OpenStudy (anonymous):

??

OpenStudy (anonymous):

omg youre soo smart :oi seriously dont even take any ap classes or anything.im from bosnia, so thats why its hard for me:/ what gpa do you have to have there?

OpenStudy (anonymous):

well i dont really know much about international admissions but i would say if you're in the top 15% of your class you have a great chance and even top 20% you have a good chance.

OpenStudy (anonymous):

LOL, my gpa is like a 3.4 weighted >.<

OpenStudy (anonymous):

do you take SAT's or ACT's or something different?

OpenStudy (anonymous):

so is that like on a 5 point scale?

OpenStudy (anonymous):

4 point scalelol

OpenStudy (anonymous):

well thats really not bad at all. to be honest, my SAT scores are what got me in here.

OpenStudy (anonymous):

what did you get?and i only took the ACTs and got 20 out of 36 :o haha, but ididnt study or anything :(

OpenStudy (anonymous):

I got an 800 math and 770 verbal

OpenStudy (anonymous):

oh i dont even know what ts out of lol

OpenStudy (anonymous):

800

OpenStudy (anonymous):

dammmmmmmmmmmm, feel free to do my homework any time(L: haha

OpenStudy (anonymous):

haha yeah im happy to help

OpenStudy (anonymous):

well anything else while im here?

OpenStudy (anonymous):

oh gosh, there is plenty, i just dont know how to sum them up lol::/ tooo much woork

OpenStudy (anonymous):

do you have a way to scan it and then send it as a file?

OpenStudy (anonymous):

omg, ill trty that loldidnt even think of it

OpenStudy (anonymous):

haha alright cool

OpenStudy (anonymous):

its being stupoid,a nd its not detecting the wirless connection:(

OpenStudy (anonymous):

hmmm well you wanna shoot me one more and then see if you're able to try the rest on your own?

OpenStudy (anonymous):

will you be on tomorrow?Lo

OpenStudy (anonymous):

umm not really sure bc i have a final tomorrow but you could always email me

OpenStudy (anonymous):

why arent you studying for that/?~? lol

OpenStudy (anonymous):

well i feel pretty good about it but maybe im procrastinating just a bit haha

OpenStudy (anonymous):

what class is it for? lol

OpenStudy (anonymous):

You're so freakin smart i swear lol. my boyfriend was trying to help me, and hes a sophomore in college, but hes just sooo stupid :/ lol

OpenStudy (anonymous):

haha he probably wouldnt be very happy to hear that

OpenStudy (anonymous):

its a class called Solids, and trust me if i tried to explain it I would bore the hell out of you

OpenStudy (anonymous):

Lol, ive told him before, many times :/So its okay, hesjust lazy. and what the hell is that hahah stupidestr name ever

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

yeah its basically about how solid thing react to heat and forces. so if you were to build a bridge, you could use the equations i learn in class to make sure it doesnt collapse when loaded with cars

OpenStudy (anonymous):

Hahah wtf, why the helllare you taking that?! haha

OpenStudy (anonymous):

im in engineering so its one of the required classes

OpenStudy (anonymous):

ehh, i cant wait till college lol, but at the samw time im scared haha

OpenStudy (anonymous):

dont be. its gonna the best time of your life i guarantee it. you know where you're goin yet?

OpenStudy (anonymous):

oh nvm we already talked about this haha

OpenStudy (anonymous):

but anyway yeah college is awesome dont worry

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