Question

6 radical 81a4b8

Answer 1

54a2b4

Answer 2

is this
\[\sqrt[6]{81a^4b^8}\]

Answer 3

ohh not 6 times all that, you mean the sixth root?

Answer 4

yes it is Satellite ^^

Answer 5

then
\[\sqrt[6]{81}=\sqrt[6]{3^4}=\sqrt[3]{3^2}\]

Answer 6

similarly
\[\sqrt[6]{a^3}=\sqrt[3]{a^2}\] and
\[\sqrt[6]{b^8}=b\sqrt[6]{b^2}=\sqrt[3]{b}\]

Answer 7

typo there, should have been
\[\sqrt[6]{a^4}=\sqrt[3]{a^2}\]

Answer 8

hope it is clear what i am doing, just taking out the common factor of 2 in the index and the radicand. put them together and get
\[b\sqrt[3]{9a^2b}\]

Answer 9

Very clear! thanks for all the help! It's highly appreciated.