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integral of [x (tan^2 x)] dx
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\[\int\limits_{0}^{\Pi/3} x \tan^2x dx\] that's the question.
try a trig identity (secx)^2-(tanx)^2 =1 so \[\int\limits_{0}^{\pi/3} x(\sec^{2}x-1)dx\]
And??? How to continue with that?
break up the integral and you could try integration by parts
thanks.
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\[\sec^{2} x = \frac{1}{cos^{2}x} \] Also \[cos^{2}x = \frac{1+ cos 2x}{2}\] and further break the integral up
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