Question

Solve log_2 (3 − x) + log_2 (−x) = 2.

Answer 1

log2(3x-x^2)=2
2^2 = 3x-x^2
0=-x^2+3x-4
x=4,-1
check for validity,

Answer 2

log_2(-3x+x²)=2
log_2(-3x+x²)=lg_2(4)
x²-3x-4=0
(x-4)(x+1)=0
x=4 or -1

Answer 3

Use the change of base formula to find log3 ()

Answer 4

Use the change of base formula to find log_3 (pi)

Answer 5

Use the change of base formula to find log_3 (pi)? different question?

Answer 6

yea

Answer 7

\[\log_{10} 3\Pi \div \log_{10} 10\]

Answer 8

or ln3(pi)/ln10

Answer 9

plug either into your calculator

Answer 10

the options i have are
a) log3/log pi
b)log(pi/3)
c) log pi/log3
d) log(3/pi)
e) log_pi(^3)

Answer 11

is the question log(base 3) (pi)? if so it would C

Answer 12

yea

Answer 13

"C"

Answer 14

logbA= logA/logb

you digg?

Answer 15

yea lol
im doing some review for my math exam i really appreciate the help
i have more questions if you dont mind

Answer 16

im studying myself.. if i can, i will answer your questions