Question

Help please :).

solve for indicated letter.

M=pir^2hd for r

Answer 1

that is pi, not pir^2, r^2 is a seperate variable

Answer 2

r = sqrt( M/(pihd))

Answer 3

lum that is not one of the answers :(

Answer 4

r= +/- sqrt(M/pihd)

Answer 5

sae jhony

Answer 6

\[r=\pm \sqrt{\frac{M}{\pi h d}}\]

Answer 7

same lala

Answer 8

same what?

Answer 9

not an answer :(

Answer 10

thats the right answer,

Answer 11

i'll type the answers, give me a minute

Answer 12

ok

Answer 13

\[r=+/-\sqrt{piMhd} over hd\]

Answer 14

\[r=+/-M \sqrt{pihd} \over pihd\]

Answer 15

\[r=+/-\sqrt{M \pi hd} \over \pi hd\]

Answer 16

\[M=\pi r^2hd,\]\[r=\pm\sqrt{\frac{M}{\pi h d}}.\]lalaly is correct...

Answer 17

\[r=+/-\sqrt{\pi Mhd}\]

Answer 18

\[r=\pm\sqrt{\frac{M}{\pi h d}}=\pm\frac{\sqrt{M}}{\sqrt{\pi h d}}=\pm\frac{\sqrt{M\pi h d}}{\pi h d}.\]They're all the same thing...

Answer 19

ohhh, thank you across, and also lala