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Mathematics 7 Online
OpenStudy (anonymous):

Simplify, using only postive exponents in your answer.

OpenStudy (anonymous):

\[\left(\begin{matrix}x^-3+y^-4 \\ x^-2+y^-3\end{matrix}\right)\]

OpenStudy (anonymous):

It is a fraction idk how to put line in between them... sorry

OpenStudy (anonymous):

the syntax is frac{ numerator }{ denominator}

OpenStudy (anonymous):

so \[ \frac{x^{-3} + y^{-4}}{x^{-2} + y^{-3}} \] ?

OpenStudy (anonymous):

yes that is it.

OpenStudy (anonymous):

Also, when you do exponentials, x^-3 should be x^{-3} otherwise the only thing raised up will be the first symbol after the ^

OpenStudy (anonymous):

oh sorry i didnt know thanks for telling me.

OpenStudy (anonymous):

to answer your question, multiply top and bottom by y^4: \[\frac{y^4}{y^4} \cdot \frac{x^{-3} + y^{-4}}{x^{-2} + y^{-3}} = \frac{y^4x^{-3} + 1}{y^4x^{-2} + y} \] and then by x^3: \[\frac{x^3}{x^3} \cdot \frac{y^4x^{-3} + 1}{y^4x^{-2} + y} = \frac{y^4+x^3}{y^4\cdot x + yx^3} \]

OpenStudy (anonymous):

so that is the final answer?

OpenStudy (anonymous):

I mean, you can split it up further if you'd like. \[\frac{y^4+x^3}{xy^4+x^3y} = \frac{y^3}{xy^3+x} + \frac{x^2}{xy^4+x^2y}\]

OpenStudy (anonymous):

I'm just trying to simplify it with only positive exponents lol

OpenStudy (anonymous):

All of the exponents are positive, so beyond that you can doctor it up as you'd like.

OpenStudy (anonymous):

Ok sounds good thanks man

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