Find the amplitude and period of f (x) = −2 cos(1/3x + 1
the amplitude is the coefficient of the function, that is 2
rewrite cos(1/3x + 1)=cos1/3[(x) +3]
Then the period will be 2pi/1/3 or 6 pi
thanks can you help Find the angle co-terminal with 23pi/3
23pi/3 = 7 and 2/3 pi. Since each revolution is 2 pi, we make 3 complete revolutions and then 1 2/3 pi more or 5/3 pi. So the angle that is co-terminal with 23pi/3 is 5/3 pi
i dont have 5pi/3 as an option
It could be - pi/3
yeah i have that option
-pi/3 is the same as 5pi/3
how do you convert from 5pi/3 to -1pi/3
5pi/3 - 2pi
ok i see
Good
you think you can help me with this one too? Find the exact value of cot (sin^-1 (sqrt2/2))
(sin^-1 (sqrt2/2) meant the angle whose sin is sqrt2/2 which is pi/4 or 3pi/4
so now the problem becomes cot(pi/4) which is 1 or cot(3pi/4) which is -1.
You might want to reread your directions carefully. If you have to give ALL the angles for which this is true, you would have to say pi/4 +k2pi and 3pi/4 +k2pi
Do you understand?
yea
for my options i have a) pi/4 b) -pi/4 c) 0 d) -1 e) 1 i have to pick between 1 and -1...how do i decide
Are we still talking about the same problem?
yea
Well then, I would go with 1 because I am assuming that you are a beginner in trig. If that right?
Is that right?
yea
So go with 1
ok kool. i have no way of telling whether its right or wrong. im just going over practice questions for a test but i understand the concept
Good for you.
Simplify sin 2k cos k + cos 2k sin k using an appropriate trigonometric identify. do you know this one?
This looks like the formula: sin(x+y) = sin(x)cos(y)+ cos(x)sin(y) sin(2k)cos(k) + cos(2k)sin(k)
It matches up so it would be sin(2k+k)=sin(3k)
yea that looks right how about sinx + (cos^2x)/(sinx)
Well, cos^2(x) = 1-sin^2(x) so if we make that substitution we would have sin(x) + 2-sin^2(x) /sin x
Is the entire thing over sin(x) or just the cos^(x)?
just the cos^(x) and we are simplyfing i forgot to mention that
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