Question

a square has an area of 49 square inches. if the same amount is added to the length and removed from the width, the resulting rectangle has an area of 45 sgaure inches. find the dimensions of the rectangle.

4in x 9in
3in x 4in
5in x 10in
5in x 9in

Answer 1

Hi there. Do you just want the answer or learn the material?

Answer 2

answer please :)

Answer 3

5x9

Answer 4

ty hun

Answer 5

You can solve this in wolfram alpha pretty easily

Answer 6

how so? i know wolfram decently well

Answer 7

can i just type the question as i did here?

Answer 8

http://www.wolframalpha.com/input/?i=Solve%5B%7Bx*x+%3D%3D+49%2C+a*+b+%3D%3D+45%2C+a+%3D%3D+x+-+y%2C+b+%3D%3D+x+%2B+y%2C+x+%3E+0%2C++++y+%3E+0%7D%2C+%7Bx%2C+y%2C+a%2C+b%7D%5D

Answer 9

what was that?

Answer 10

that's how i solved your problem

Answer 11

the original dimension is X, so you know X*X=49.
You have a new rectangle, of dimensions A*B, and the area of that is 49.
You know A is X minus some length (Y).
You know B is X plus that same length (Y).

Just put all those facts into wolfram alpha together and the answer pops out, a=5, b=9. THat's how I solved your question.

Answer 12

thank ya!

Answer 13

If the area of a square is 49, then the each side length is 7. Let x be the amount to add and subtract from 7. Solve the following for x:
(7 + x) (7 - x) = 45
x = 2
9 * 5 = 45
The answer is not in the problem selection list.