Question

A gun is fired horizontally at the center of a target's bull's eye. If the target is located 100m away and the bullet is traveling 500 m/s, how far beneath the center of the bull's eye does the bullet impact?

Answer 1

classic kinematic problem

Answer 2

yeah, but idk where to start..

Answer 3

bullet verticle equation
h(t)= h_0 + v_0t + 1/2 a t^2

gravity =a=-9.8

h(t) = -4.9 t^2

Answer 4

we gotta find t

velocity 500m/s to travel 100m

m/(m/s) = s

100/ 500 = 1/5 sec

Answer 5

h(t) = -4.9 ( 1/5)^2

Answer 6

.196

Answer 7

so, .196 m below the bulls eye?

Answer 8

yes?

Answer 9

Wow, that's really easy...

Answer 10

Bro, your amazing.. I have a couple others ima stuck on... you mind?