Question

log help

Answer 1

whats up?

Answer 2

sec.

Answer 3

kk

Answer 4

\[\log_{3}46/2 = \log_{10}46/2\log_{10}3 \] ?

Answer 5

text says to do it one way, prof says another way but they yield different answers.

Answer 6

hm, calculator, or no calculator?

Answer 7

3^2x=46 is the original problem. The book says to take log 10 to each side and pull the 2x in front of the log.. my prof says to log 3 to each side

Answer 8

so book gets x=\[\left(\begin{matrix}\log46 \\2\log3 \end{matrix}\right)\]

Answer 9

Lol, mkay, so you just take the log of each.
~log3^2x=log46
~2xlog3=log46
~x=(log46)/(2log3)

Answer 10

then that equals like 1.742...... plug it back in and its pretty exact.

Answer 11

so it doesnt work do log 3 to each side?

Answer 12

gimme a sec..

Answer 13

\[\log_{3} 3^{2x}=\log_{3} 46\]

Answer 14

no, long answer short, when u divide JUST the log3 over, then the '2' you mess up the equation. not gunna explain why unless u want me too

Answer 15

hmm

Answer 16

\[2^{x-1}=7\]

Answer 17

i get \[\log_{2} 7+1\]

Answer 18

yeah, i got (log7 / log2) +1 same answer

Answer 19

is that the same then as \[\left(\begin{matrix}\log7 \\ \log2\end{matrix}\right)+1\]

Answer 20

without parens.. i dont know how to do fractions otherwise

Answer 21

ok nm i am too slow

Answer 22

thanks for your help.

Answer 23

yeah it is. Im pretty sure.