Question

3x/4+3=27 still dont get these

Answer 1

32

Answer 2

32

Answer 3

3x+12/4=27
3x=96
x=32

Answer 4

babs ill go through it step by step if u need

Answer 5

\[(3x/4)+3=27\]
\[(3x/4)=27-3\]
\[(3x/4)=24\]
\[3x=4*24\]
\[x=32\]

Answer 6

thanks having a hard time understanding lineat eguations it aint my best math prob

Answer 7

3x/4+3=27
*4 *4 (Multiply each side by its denominator, in order to get rid of the fraction)

3x + 3 = 108
- 3 -3 (Subtract 3 from each side)

3x = 105
/3 /3 (Divide it by three)

x = 35


Remember PEMDAS

P =parenthesis
E = exponent
M = multiply
D = divide
A = add
S = subtract

Answer 8

\[(3x/4) + 3 = 27\]
you want to get x by its self x = something in order to do that you subtract 3 from both sides of the equation
\[(3x/4) + 3 -3 = 27
-3 \]
\[3x/4 = 24\] now you multiply both sides by 4 in order to make it 3x=(27*4)
then divide both sides by 3 and it be comes x=(27*4)/3 = 32

Answer 9

you do the inverse of what is done to the x side of equation to cancel it out of that side and in order to make it so you dont change the equation what ever you do to one side you have to balance it by doing the same to the right side of the equation.

Answer 10

lol thanks somebody finally exsplains it all to me cuz im like failing them with a 15% and it aint good

Answer 11

you want to get x by it's self and you have to keep the equation balance think of it as a scale balance

Answer 12

to get x by its self you need to subtract from it if something is added divide if its multiplied by something or the inverse

Answer 13

post another one that u make up and ill explain that one to u
try to stump me :-)

Answer 14

no stumping u online math it suxs