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Mathematics 13 Online
OpenStudy (anonymous):

|x + 3| < 10 is x < 7 ; x > -7 ?

OpenStudy (anonymous):

Swing and a miss

OpenStudy (anonymous):

-13 < x < 7

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

like can you show me the work?

OpenStudy (anonymous):

Do you know what the | | signs mean?

OpenStudy (anonymous):

absolute value

OpenStudy (anonymous):

yes -7<x<7

OpenStudy (anonymous):

so it's correct? :]

OpenStudy (anonymous):

Lol, there was me hoping you'd type everything out for me do_0b.ie, but no, you're wrong.

OpenStudy (anonymous):

yea, just plug in the numbers

OpenStudy (anonymous):

You're hopelessly wrong, sorry.

OpenStudy (anonymous):

still wrong

OpenStudy (anonymous):

-13 < x < 7 is the answer

OpenStudy (anonymous):

how'd you do it strobe?

OpenStudy (anonymous):

-13 < x < 7 forgot negative side

OpenStudy (anonymous):

The way I do it is just picture the graph in my head and see where it intersects the line y = 10. This is quick but not formal, do you need the formal working?

OpenStudy (anonymous):

haha

OpenStudy (anonymous):

just how'd you got the answer. like if you added, subtracted, multiplied. :)

OpenStudy (anonymous):

| x + 3 | < 10 => x + 3 < 10 AND x + 3 > - 10 => x < 7 AND x > -13

OpenStudy (anonymous):

for this one -7 < x+3 < 10

OpenStudy (anonymous):

subtract 3 from both sides

OpenStudy (anonymous):

now i see it (: thanks!!

OpenStudy (anonymous):

No problem, I would suggest drawing it as a graph if you cant get the answer. Helps you see the answer.

OpenStudy (anonymous):

-10 < |x + 3| < 10 -10 - 3 <x<10-3 -13< x < 7 since it is less than 10 the domain is (-13,7) look at the number line |dw:1323388902923:dw| Notice I used round brackets instead of square because it never hits -13 or 7 it gets infinitely close to them

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