Prove that the integral from 0 to infinity sinx/x =pie/2
\[\int_0^{\infty} \frac{\sin {x}}{x}\]
hmm did you try by parts ??
integration by parts
no. I havent
i am confused about the x in denominator i dunno how to get rid of it
i think it's Si(x) function not sure lemme check
Hmm i dunno about them sorry I won;t be able to help you
this site http://tutorial.math.lamar.edu/Classes/CalcII/IntegrationStrategy.aspx says that the integral can never be solved except with an algebra system
algebra system hmm sounds advanced yet interesting
certainly
can working be shown as to how you can arrive at the answer?
did u take fourier series?
I seriously have no idea on how to do this, i have to study much more to get on something like this
lalaly I didnt but could u give me insight on that?
you can write it as a double integral and then switch the order of integration... \[\int\limits_{0}^{\infty}\frac{\sin(x)}{x}dx=\int\limits_{0}^{\infty}\int\limits_{0}^{\infty}e^{-xt}\sin(x)dtdx\]
thanx Ishaan I will await your reply
Zarkon could you please finish it up for me?
I really don't want to ;)...switch the order of integration...then use parts on the first integral...you will end up with a standard inverse trig integral
thanx Zarkon
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