Question

Select the inequality that models the problem.

The length of a rectangle is twice its width. If the perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?

(Points : 4)
2*2w + 2w < 50

2 + 2w < 50

2w*w < 50

2w < 50

Answer 1

perimeter is 2(length + width)
so we have 2(l+w)
but l=2w
therefore
perimeter is 2(2w+w)
which is less than 50
so the answer is 1st option