Question

f'(x)=(2 ln(x))/x
How do I find the x value? I put the equation equal to zero, but I do not know any log rule to solve it for x value. I need help please.

Answer 1

Do you want to solve the equation for x?

Answer 2

Yes

Answer 3

That's not possible, unless you're setting f'(x)=0.

Answer 4

Are you trying to find maxima/minima?

Answer 5

\[\frac{2\ln(x)}{x}=0\]doesn't seem too bad.

Answer 6

if you are looking for critical value , look for where function diverge too

Answer 7

How do I proceed after this to find the value for x?

Answer 8

Yes I am looking for critical values

Answer 9

what happened if you plug in 0 for x

Answer 10

you can't take the ln(0). There has to be some other way related to log rules to solve this question, and I can't figure it out.

Answer 11

it diverges, which mean it is a criticle point.

a critical point of a function of a real variable is any value in the domain where either the function is not differentiable or its derivative is 0

Answer 12

\[\frac{2\ln(x)}{x}=0,\]\[2\ln(x)=0,\]\[\ln(x)=0,\]\[x=1.\]