3√45x^3 + 2√12 + √27 - 3√20x^3

Question

anonymous · Answer

$$9\sqrt{5x^3} + 4\sqrt{3} + 3\sqrt{3} - 6\sqrt{5x^3} = 7\sqrt{3} + 3\sqrt{5x^3}$$

anonymous · Answer

When you siimplify the radical for instance $$2\sqrt{12}$$ first rewrite 12 as $$2 * \sqrt{4 * 3} = 2*\sqrt{4}*\sqrt{3} = 2*2*\sqrt{3} = 4\sqrt{3}$$ Thats how you simplify the radicals when you have a number in front

anonymous · Answer

Thank you. But the answers I can choose from are:
a. 40x√x
b. 3x√5x + 7√3
c. 3x√10x + 7√6
d. 10x√8x

anonymous · Answer

2√12 = 2*2*√3 = 4√3
√27 = 3√3
3√45x^3 =   9√5 x^3
-3√20x^3 = - 6√5x^3
adding you get
3√5x^3  + 7√3

anonymous · Answer

oh its b then
the x^3 is contained in the square root