Question

decompose into partial fractions

(x^2+x-5)/((x-1)(x^2-2))

Answer 1

Lagrangeson!

Answer 2

Ax +b C
------ + -------
x^2-2 (x-1)

Answer 3

why ax+b?

Answer 4

because (x^2-2) is not factorable into linear

Answer 5

It's \(ax+b\) because the denominator of that fraction has degree 2. You can also bypass this by decomposing in the following manner.\[\frac{x^2+x-5}{(x-1)(x^2-2)} = \frac{A}{x+\sqrt 2}+\frac{B}{x-\sqrt{2}}+\frac{C}{x-1}\]

Answer 6

oh, thx