What is the solution set of the absolute value sentence |x + 9| < 2?
Two principles can help here: \[|a|^2=a^2\]and if\[a<b \text{ then }\]\[a^2<b^2 \text{ ; where }a,b>0\]
ok when have | | < or > any number it will be come as: -2< x+9< 2 then u jst has 2 let x alone by give -9 to both side here it 'll be -11< x< -7 thts it up to ths kind of question
now give me another ques if theres = insted of <
| | sign means "absolute value" meaning the sign inside the | | doesn't matter, it will always be positive. for example; |-9|=9 |9|=9 and you can solve this inequality just like solving equations.
x<-7
The | | sign does matter for inequalities. Not all x < -7 work, take -100 for example: |-100+9|=|-91|=91. 91 is most definitely not less than 2.
\[\large{-2<x+9<2}\]now subtract 9 from both sides\[-11<x<-7\]
ohh I see, How did it become -2< x+9< 2 ??? I just want to know. :)
there is rule that if where c should be positive
-2<x+9<2 -11<x<-7*this is the answer
Join our real-time social learning platform and learn together with your friends!