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what is the laplace inverse of (s^4+6s-18)/(s^5-3s^4)?
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use partial fractions and take s^4 common from denomiator it will be easy to solve
and then use the formulae that laplace inverse of 1/s = 1 and laplace inverse of 1/s^2= t etc and laplace inverse of 1/s-3= \[e^{3t}\]
the answer is (e^(3t) )+t^3
would you please give me the solved question
do you know how to make partial fractions??
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yes
then use partial fractions and it will be easy use the formulae i mentiond above
is it form bsc?? methods
s^4+6s-18=A/s+B/s^2+C/s^3+D/s^4+E/s-3
yes right and then find A,B,C,D,E AND IT WILL BE 101 PERCENT SIMPLE
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ok thanks alot
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