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ln(2+e^(-x)) =2
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\[\ln \left( 2+e ^{-x} \right)=2, x=-\ln (2-e ^{2}), is this correct? ;;;\]
nope
\[x=-\ln (e ^{2}-2)\]
thats correct :) thanks
can you explain the steps to get this answer?
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\[\ln a = b, --> a = e ^{b} ,,, (2+e ^{-x})=e ^{2},,, e ^{-x}=e ^{2}-2\] take ln again then you have the answer
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