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solve the differential equation: dy/dx=(√y)cos^2(√y)
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This equation is separable: \[ \int \frac{dy}{\sqrt{y}\ \ \cos^2 \sqrt{y}} = \int dx \] Now substitute \( u = \sqrt{y} \).
Ummmm but I will face a problem with "cot^2"
No, with sec^2. And this is the standard derivative of another trig function.
\[ (d/dx) \tan x = \sec^2 x \]
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Ok.. I will try to solve it.. but just give me "final result"
My dear!! where are you?
Are you still facing a problem?
dy/dx=(√y)cos^2(√y) \[\int\limits_{}^{}dy/\sqrt{y }\cos^2 \sqrt{y}= \int\limits_{}^{}dx\]
\[\int\limits_{}^{}\sec^2 \sqrt{y}dy/\sqrt{y}=x+C\]
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\[2\tan \sqrt{y}=x+C\] y=[tan^-1 (x+C)/2]^2
mark 0 ,,, Thank so much..
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