A boy whirls a stone with mass 250g in a horizontal circle of radius 1.5m and at height 3.0 m above level ground. The string breaks, and the stone flies off horizontally and strikes the ground after travelling a horizontal distance of 8m. What is the magnitude of the centripetal acceleration and the centripetal force of the stone during circular motion?

Question

anonymous · Answer

D= (1/2)at^2+(v(initial)*t)
3 = .5*9.8t^2 + 0
t= .2474 s

horizontal velocity = 8m / .2474 s = 32.3363 m/s
 cent. acc. = v^2/r
cent. acc. = 32.3363/1.5 = 697.091 m/s^2  <----Answer

F = ma
F=.250*697.091=
F=174.273 kg * m/s^2 or N <----Answer