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Mathematics 12 Online
OpenStudy (anonymous):

can someone help me with curl and divergence, and green's theorem?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

I can help with curl and divergence at least

OpenStudy (anonymous):

my instructor did some examples and when evaluating an integral, and you use green's theorem, the result for curl and divergence should be the same

OpenStudy (anonymous):

but when a problem in the book asks you to find the circulation and flux, the answers are different

OpenStudy (anonymous):

they are not supposed to be same in general, your professor probably did a special problem

OpenStudy (anonymous):

Divergence results in a scalar, curl in a vector. They generally would not be the same.

OpenStudy (anonymous):

i think i am confused, he linked circulation and curl together, and flux and divergence together...i guess just for calculation's sake, he was just referring them to each other to help us remember?

OpenStudy (anonymous):

yes, curl is about circulation while divergenc is about flux

OpenStudy (anonymous):

ok thank you. i get how to do the calculations but wasn't understanding what i was doing exactly. but i do have a very simple problem that i'm not getting the right answer for. i will post...

OpenStudy (anonymous):

F=(x-y)i+(y-x)j. C: square bounded by x=0, x=1, y=0, y=1. use green's theorem to find ccw circulation and outward flux

OpenStudy (anonymous):

for flux: M=x-y, N=y-x correct?

OpenStudy (anonymous):

divergence at a point = dU/dx + d V/ dy = 1+ 1=2

OpenStudy (anonymous):

yes, that's the answer i'm not getting...i get 0

OpenStudy (anonymous):

you have to do \[M_x + N_y\]

OpenStudy (anonymous):

i like using double integral so it should be double integral (dV/dx-dM/dy) dxdy

OpenStudy (anonymous):

oops, (dV/dx-dU/dy). i'm use to using M and N

OpenStudy (anonymous):

in order to use the double integral, the form of the original equation has to change to closed loop integral (Vdy-Udx)

OpenStudy (anonymous):

so just integrate the divergence of 2 over your region \[\int_0^1\int_0^1 2 dx dy\]

OpenStudy (anonymous):

then you define V and U. and then it's double integral dU/dx+dV/dy)dxdy. sorry i made a mistake earlier.

OpenStudy (anonymous):

well my new U and V are: U=y-x and V=-x+y

OpenStudy (anonymous):

dU/dx= -1, dV/dy= 1. dU/dx+dV/dy=0

OpenStudy (anonymous):

i follow this form for other problems which work but not for this.

OpenStudy (anonymous):

i must be doing something wrong

OpenStudy (anonymous):

Since your field is conservative , the green theorem should turn out be zero

OpenStudy (anonymous):

so what i've been doing is green's theorem? ahhhhhh ok so to find flux, it's simply Mx+Ny?

OpenStudy (anonymous):

or what is the difference??? what is green's theorem used for?

OpenStudy (anonymous):

you don't need to do green theorem if the field is conservative, it is always zero

OpenStudy (anonymous):

Green theorem is for line integral on closed path of non-conservative field

OpenStudy (anonymous):

i thought it's zero for circulation cuz conservative means the terms will cancel out since they're equal. this is the case for flux too?

OpenStudy (anonymous):

I don't think so

OpenStudy (anonymous):

i will work out some more probs thanks for your help

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