Question

what is the range of this function y=(x^2-1)/(x-1)
i though it was real numbers but its wrong

Answer 1

think of what happens when x=1

Answer 2

its undefined

Answer 3

correct - so its range is all real numbers except 1

Answer 4

oh ok so its same as domain

Answer 5

yes

Answer 6

whats domain?

Answer 7

domain is the values for x for which the given function is valid.

Answer 8

it would be all real numbers except1

Answer 9

sorry

Answer 10

thank you

everyone

Answer 11

the domain is all the x-values, and the range is all the y-values.

Answer 12

yeah

Answer 13

so your question is asking for the range

Answer 14

There is a "hole" at (1,2); y=2 is not in the range

Answer 15

correct @Mandolino

Answer 16

oh ok

Answer 17

\[y=\frac{x^2-1}{x-1}=\frac{(x-1)(x+1)}{x-1}=x+1\]where\[x \ne1\]

Answer 18

\[y=\frac{x^2-1}{x-1}=\frac{(x+1)(x-1)}{x-1}=x+1\]so when x=1 y=2
but x=1 in not in the domain.

Answer 19

snap!

Answer 20

oh ok

Answer 21

sorry for the confusion earlier on :-)

Answer 22

its all good