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Could someone show me how to find the absolute extrema for the function f(x)=(4/x)+ tan(πx/8) on the interval [1,2]?
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ok so we do the same as before
find f'(x)
set it equal to zero
find the x's that satisfy f'(x)
then plug them back into your original equation to get your y values
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find f' and put the values of ur intrval and find abolute max
I run into some confusion when I do find the derivative... I came up with f'(x)=(-4/x^2) + sec^2(πx/8) + tan(π/8)... Am I on the right track?
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