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a flywheel has a moment of inertia of 2.3 kg*m^2. What is the average power needed to spin it up from rest to an angular velocity of 70 rad/s. in 30 seconds
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As you should have learned previously, the translational kinetic energy equation is \[K=(1/2)mv^2\] Similarly, rotational kinetic energy is \[K=(1/2)Iv^2\] Where I is your moment of inertia. \[K=(1/2)(2.3 kg*m^2)(70 rad/s)=80.5J\] This is the work that must be done (we are not dealing with potential energy, solely kinetic). Now, solve for power using \[P=W/t\]
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