Question

Short Answer: Raise the quantity in parentheses to the indicated exponent, and simplify the resulting expression. Express answers with positive exponents. (28xy^3/130x^3y^-2)^3

Answer 1

Jimmy do you think you can help me

Answer 2

ill be back - just been called away

Answer 3

okay

Answer 4

sorry everyone the problem is wrong let me repost it k

Answer 5

oh...this is messy!
When you raise an exponent to an exponent, like that 3y^-2, you have to treat it like 'normal' powers.
that power would simplify to 1/9x^2
which is the power that you're raising 130x to.

Answer 6

(28xy^3/140x^3y^-2)^2 is the actual problem

Answer 7

ok...my previous reply still stands.

Answer 8

don't you have to multiply the exponents to get the right answer or do you add them?

Answer 9

wouldn't it look like thing 28*28 x*x y^3*y^3/140*140*x^3*x^3y^-2y^-2 is how the problem really looks right

Answer 10

no, you multiply them like here:\[(x ^{3})^{4}\]
this would where it simplifies to \[x ^{?}\]
you add them here:\[x ^{2}*x ^{3}\]
which equals
\[x ^{5}\]

Answer 11

not quite, you have to simplify the exponents in the denominator, get it down to one "layer"

Answer 12

how do I do that

Answer 13

I said before, up there^

Answer 14

Sinz do you know that y on exponent -2 = 1/y squared
yes ?

Answer 15

so basically break the equation down to this

28/140 x/x^3 y^3/y^-2 all by ^2 right

Answer 16

I said before, up there^

Answer 17

x^-a is equal to 1/x^a

Answer 18

I said before, up there^

Answer 19

you need correcting this cathy

Answer 20

okay

Answer 21

Sinz do you know the result now sure ?

Answer 22

oops...x^3/x^2=x^1

Answer 23

yes this was

Answer 24

was that what you were talking about?

Answer 25

yes because you have wrote there x squared divide x squared = x

Answer 26

still a little confused but trying to figure it out also on paper to see how it works

Answer 27

ok write it here please

Answer 28

so I have to use the PEMDAS law to solve this problem do everything in the parenthesis and go from there

Answer 29

yes..I guess.

Answer 30

after you will can understanding it how you need to solve it will see that is very easy

Answer 31

(28xy^3/140x^3y^-2)^2 this is what I am trying to solve

Answer 32

so if that's the case then I would sit there and double everything in the parenthesis first right

Answer 33

yes i want you say that first you need to make that calcule inside parantheses

Answer 34

so simplify the stuff inside parenthesis, and such.
not doubling, taking it all to the power of two, multiplying all that by all that.

Answer 35

okay so it is 28^2 x^2 y^5/140^2 x^5y^4 right?

Answer 36

the denominator should be 140^2 x^2/(9x^2, I believe

Answer 37

my answer would look like this 784y/x^3 is that right

Answer 38

sorry miss calculated it is .14y/x^3

Answer 39

not is correct

Answer 40

oops...I've been reading the problem the wrong way.
I got y^10/25x^4

Answer 41

jhonnyy9, is english your second language?

Answer 42

jhony how would you do the problem could you help

Answer 43

yes cathy but your last answer is the right answer sure

Answer 44

XD you think my name is cathy? (I know most people abbreviate screen names here)

Answer 45

but how did she get the answer that is the question

Answer 46

sorry

Answer 47

Sinz

Answer 48

??

Answer 49

first you need calcule inside parantheses

Answer 50

so 28/140 = 1/5

Answer 51

or .2

Answer 52

x/x3 = 1/x2

Answer 53

I'm a she now!!! :D
sorry...off topic
I worked it all out on paper,
I first simplified the denominator, the bottom half of the fraction.
then I wrote it out and multiplied all the like terms.

Answer 54

yes, you have to simplify the parentheses completely, first.

Answer 55

and y on exponent -2 = 1/y2 but because this is in denominator so than y2 will being part of numinator

Answer 56

ok ?

Answer 57

okay

Answer 58

and at finaly

Answer 59

you don't even have to write y^-2 as 1/y^2, because it goes away when you simplify the ys in the fraction.

Answer 60

you see now why will be the answer y10/25x4

Answer 61

cathy no you not can simplify the y from the fraction never

Answer 62

okay so you had to add the y^-2 to the numerator right which made it y^5?

Answer 63

so because there is y3/y on -2 this is equal y on (3-(-2))= y on (3+2) =y on exponent5

Answer 64

and y5 squared is y10

Answer 65

okay now I understand

Answer 66

\[(_{140x ^{3}y ^{-2}}^{28xy ^{3}})^{2}\]
=\[(_{5x ^{2}y ^{-2}}^{1*1*y ^{3}}])^{2}\]
=\[(_{5x ^{2}}^{y ^{5}})^{2}\]
=\[_{25x ^{?}}^{y ^{10}}\]

Answer 67

all is sure ?

Answer 68

yes I am sure and cathy thank you for the breakdown it is understandable.

Answer 69

so than good luck bye

Answer 70

you too

Answer 71

you're talking to a newly-discovered girl who's now named Cathy...glad to help! :D

Answer 72

XD Thank you will be posting more problems so be wary

Answer 73

ok! :D