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Mathematics 16 Online
OpenStudy (anonymous):

Convert the base-ten number to a number in the indicated base: 396 to base twelve

OpenStudy (jamesj):

what is 12 in base 12?

OpenStudy (anonymous):

$$ \text { Assuming 12 is decimal } 12_{10} = 10_{12} $$

OpenStudy (jamesj):

Hence \[ 24_{10} = 20_{12} \] \[ 36_{10} = 30_{12} \] Following, My?

OpenStudy (anonymous):

not really..:((

OpenStudy (anonymous):

@JamesJ even I am getting your clue :P

OpenStudy (jamesj):

What are the first 11 numbers in base 12? We write them as 1,2,3,4,5,6,7,8,9,A,B Then 12 (base 10) in base 12 is 10 To make it clear that this "10" isn't ten, we usually write the subscript \[ 10_{12} \]

OpenStudy (jamesj):

Ok. Given that, how would we write in base 12, the decimal number, the base 10 number 13?

OpenStudy (anonymous):

$$ \text {Anyways, assuming 396 is decimal } 396_{10} = 290_{12} $$

OpenStudy (anonymous):

When you need to convert a decimal to another base we do it by dividing the number by the desired base and collecting the remainder in each step. This follows directly from the definition of positional system which represent any numbere as a polynomial of a radix r

OpenStudy (anonymous):

then?

OpenStudy (anonymous):

then what ?

OpenStudy (jamesj):

FFM, since you've given the answer, it's all yours now to explain it.

OpenStudy (anonymous):

James, I would love to .. but I don't understand hir query .. "then?"

OpenStudy (anonymous):

FFM,then, how can u have 290?

OpenStudy (zarkon):

\[396=\underline{2}\times 12^2+\underline{9}\times12^1+\underline{0}\times12^{0}\]

OpenStudy (anonymous):

FFM, please, explain...

OpenStudy (anonymous):

This is how I did this is actually same what Zarkon posted .. just the short ways : |dw:1323633381698:dw|

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