Question

what is the formula for frequency in calculus?

Answer 1

Frequency of what?

Answer 2

\[\omega/2\pi\]

Answer 3

you have to tell us what

Answer 4

y=4sec(pi-5pix)

Answer 5

\[\omega\]=5pi

Answer 6

so 5/2

Answer 7

yes

Answer 8

thanks :)

Answer 9

what would be the initial phase?

Answer 10

y=4sec(pi-5pix)

plug in 0 for x

Answer 11

y= 4 Sec (pi)

-4

Answer 12

my options are pi, 0 , pi/2, -pi/2 and -pi

Answer 13

Purely trigonometric functions take the following form:
\[ y = A \sin(\omega x + \phi)\]
where A is the amplitude, omega is the angular frequency, and phi is the initial phase.

Answer 14

pi

Answer 15

wrong :(

Answer 16

It is perhaps a difference in notation. I write
\[ A \sin(\omega x + \phi)\]
but it's perfectly okay to write
\[A\sin(\omega x - \phi)\]
and it would mean exactly the same thing. If this is how you have been taught, then the answer should be -pi, but you should note that they're exactly the same.

Answer 17

yes i got it :D what about for y=-4 sex(5/4 pi x) +4?

Answer 18

It would be zero in that case.

Answer 19

alright thank you so much