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Mathematics 11 Online
OpenStudy (anonymous):

subtract.

OpenStudy (anonymous):

\[\left(\begin{matrix}5x-4y \\ x^2+4xy-5y^2\end{matrix}\right)-\left(\begin{matrix}4x+2y \\ x^2+3xy-4y^2\end{matrix}\right)\]

OpenStudy (mathmate):

Assuming these are vectors: Subtract line by line. I'll do the first. (5x-4y)-(4x+2y)=x-6y

OpenStudy (anonymous):

so now subract the bottom 2 and then what after that

OpenStudy (mathmate):

The result will be another vector formed by the two differences.

OpenStudy (anonymous):

so subtract the 2 answers i just got and jw what did you get for the bottom 2 i wanna make sure i got it right

OpenStudy (mathmate):

I get xy - y^2

OpenStudy (anonymous):

ok now subtract the 2 we just got?

OpenStudy (mathmate):

Your answer will be a vector, the top of which is the first difference, and the bottom one is the second difference. \[\left(\begin{matrix}x-6y\\ xy-y^2\end{matrix}\right)\]

OpenStudy (anonymous):

(x+3y)(x-9y)over(x-y)(x+5y)(x-5y)

OpenStudy (anonymous):

@ mathmate is that the answer or is that what i need to subract sorry i was busy

OpenStudy (mathmate):

Have you been working on vectors? What you typed looked like vectors to me. If they are vectors, then what I posted would be the answer, because each element is obtained by subtraction of the corresponding elements. If they are not vectors, you have to explain to me what they are (fractions, rational functions, etc.)

OpenStudy (anonymous):

yes they are vectors i should have stated that earlier my apologies.

OpenStudy (mathmate):

Great!

OpenStudy (anonymous):

thanks!

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