Question

Please help!

Answer 1

it is translated to the right
\[\frac{\pi}{4}\] units

Answer 2

shifted to the right

Answer 3

in general if p is a positive number the graph of
\[y=f(x-p)\] is a shift to the right p units compared to the graph of
\[y=f(x)\] this has nothing really to do with secant

Answer 4

\[\csc(x)=\sqrt{2}\iff \sin(x)=\frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{2}\]

Answer 5

on the interval
\[[0,2\pi)\]this occurs at
\[\frac{\pi}{4}\]and
\[\frac{3\pi}{4}\]

Answer 6

oh but your interval is larger, it is
\[[-2\pi,2\pi]\]

Answer 7

so also
\[-\frac{5\pi}{4}, -\frac{7\pi}{4}\]

Answer 8

so it would be option 2?

Answer 9

uh no i don't think so

Answer 10

at \[\frac{5\pi}{4}\] sine is negative and therefore so is cosecant

Answer 11

but none of my options have -5pi/4, -7pi/4