To test H0:Mu=30 versus H1:Mu<30, a simple random sample of n=12 is obtained from a population that is known to be normally distributed with standard deviation = 4.5. I need to use the 6 step p-value method.
\[\overline{x}=\text{?}\]
Oh wait, xbar = 28.6. Can't believe I didn't see that before...
So I use the xbar-mu/standarddev/sqrt n?
yes...that is your test statistic
alrighty...
Okay, so I got -1.07, now I look that up on a negative Z-table?
yes
Alright, .1423, is that the P-value?
If that is what your table gives you...using my calculator I get .140579286609
what do you get with z=-1.08
.1423
I thought that was with -1.07
Oh, so where did you get -1.08?
That's .1401
i rounded...z=-1.07772050249
Oh, okay.
So what do I do with that number? Is that the p-value?
based on that number do you think you should reject the null hypothesis?
I reject if the p value is less than the level of significance, so since .1401 is greater than .05, I don't reject?
correct ... you would not reject the null hypothesis
Alright, thanks for the help.
np
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