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Mathematics 9 Online
OpenStudy (anonymous):

To test H0:Mu=30 versus H1:Mu<30, a simple random sample of n=12 is obtained from a population that is known to be normally distributed with standard deviation = 4.5. I need to use the 6 step p-value method.

OpenStudy (zarkon):

\[\overline{x}=\text{?}\]

OpenStudy (anonymous):

Oh wait, xbar = 28.6. Can't believe I didn't see that before...

OpenStudy (anonymous):

So I use the xbar-mu/standarddev/sqrt n?

OpenStudy (zarkon):

yes...that is your test statistic

OpenStudy (anonymous):

alrighty...

OpenStudy (anonymous):

Okay, so I got -1.07, now I look that up on a negative Z-table?

OpenStudy (zarkon):

yes

OpenStudy (anonymous):

Alright, .1423, is that the P-value?

OpenStudy (zarkon):

If that is what your table gives you...using my calculator I get .140579286609

OpenStudy (zarkon):

what do you get with z=-1.08

OpenStudy (anonymous):

.1423

OpenStudy (zarkon):

I thought that was with -1.07

OpenStudy (anonymous):

Oh, so where did you get -1.08?

OpenStudy (anonymous):

That's .1401

OpenStudy (zarkon):

i rounded...z=-1.07772050249

OpenStudy (anonymous):

Oh, okay.

OpenStudy (anonymous):

So what do I do with that number? Is that the p-value?

OpenStudy (zarkon):

based on that number do you think you should reject the null hypothesis?

OpenStudy (anonymous):

I reject if the p value is less than the level of significance, so since .1401 is greater than .05, I don't reject?

OpenStudy (zarkon):

correct ... you would not reject the null hypothesis

OpenStudy (anonymous):

Alright, thanks for the help.

OpenStudy (zarkon):

np

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