Question

Solve: 4^(2x-5)<=3^(x-3)

Answer 1

i'm not sure of what i should do first

Answer 2

do you mean \[4^{2x-5}=3^{x-3}\] ?

Answer 3

no. i meant \[\le\] sorry

Answer 4

Are you doing logarithms or is this just an exponential problem?

Answer 5

i'm working with logarithms. i just don't know what to do next

Answer 6

Okay great. I am too. What you have to do is make both sides have the same base. This isn't usually possible but it can be done using log. What you do is rewrite the problem as
\[\log 4^{2x-5}=\log 3^{x-5}\]
Can you take it from there?

Answer 7

Replace the equal sign with\[\le\] sorry

Answer 8

\[2x - 5 \log_44 = x \log_43 - 5\log_43\]
Now solve it \(\log_44 = 1\)

Answer 9

I don't understand this, why is everything in log 4?

Answer 10

Because I chose to

Answer 11

It's my choice I could have choose \(\log_3\) as well

Answer 12

or Natural Log \(\ln\)