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Mathematics 24 Online
OpenStudy (anonymous):

how do you find the multiplicative inverse of a complex number?

OpenStudy (anonymous):

you want the answer or the method?

OpenStudy (anonymous):

method

OpenStudy (anonymous):

ok suppose you are given \[a+bi\] and you want to solve \[(a+bi)(x+iy)=1\] for x and y. this is the same as solving \[x+iy=\frac{1}{a+bi}\] for x and y, and you compute \[\frac{1}{a+bi}\] as you would any complex division

OpenStudy (anonymous):

multiply numerator and denominator by the conjugate of the denominator \[\frac{1}{a+bi}\times \frac{a-bi}{a-bi}\] and write your answer in standard form

OpenStudy (anonymous):

so what if it's 4i/(3+1)

OpenStudy (anonymous):

you lost me there. \[\frac{4i}{3+1}=\frac{4i}{4}=i\]

OpenStudy (anonymous):

multiplicative inverse of \[i\] is \[-i\] because \[i\times -1=1\]

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