Question

The solution to this question has been evading me for a while. This is technically a simple physics problem.

If a projectile is to be launched at a given angle theta, height 'h' and distance 'd'. Determine an equation to find the initial velocity.

Answer 1

\[I=\int_{t_0}^{t_1} f(t) dt=mv_1 - mv_0\]

\[v_0=0\] so

v=\[\frac{\int_{t_0}^{t_1} f(t) dt}{m}\]

Answer 2

Hmm initial Velocity, Velocity when Height = 0?

Answer 3

right after you launch it

Answer 4

or by h he(hades) means maximum height and d for range

Answer 5

oh hmm

Answer 6

I though he meant what would initial velocity depend on?

Answer 7

I am confused on this one :-/

Answer 8

It could be either, but other case is much easier

Answer 9

why would i need an to derive a equation for initial velocity of a projectile, i just need to kick it with some velocity and find the velocity at some point later

Answer 10

I read it one way last night, and differently now

Answer 11

maybe he is saying get the initial velocity of a projectile who is at height h and distance d from the point of launch and umm makes angle alpha with x axis

Answer 12

so is h , height kicked from , or the height it goes to?

Answer 13

i am thinking of the height 'h' it goes to

i haven't seen a question like this before, i am really confused about this

Answer 14

I think it's better if we leave it alone

Answer 15

i mean i don't get it
okay hmm lets say i place a ball a meter above the ground and decide the angle it should be kicked on and lets say at distance d from some point now the initial velocity is completely dependent on how hard i kick the ball, why would be there an equation for how hard a ball should be kicked

i could be wrong :-/

Answer 16

yeah it's better to leave it alone