Question

If motion of a particle given below is
x=u(t-2s)+a(t-2s)^2
A)initial velocity is u
B)acceleration is a
C)acceleration is 2a
D)at t=2s particle is at origin
More than 1 option can be right
Please explain ure answer.

Answer 1

s is seconds just a unit

Answer 2

A,C and D are true :-)

Compare it with \(x = u\times t + \frac{1}{2}\times a \times t^2\)

Answer 3

actually ure wrong..i wont tell u the rite answer try it!!

Answer 4

I can't be wrong

Answer 5

and please explain...

Answer 6

no u hav to expand then compare

Answer 7

Na I don't have to expand since (t - 2) is time only (2 is in seconds and so is t)

Answer 8

but its not a(t-2s)^2 its supposed a/2

Answer 9

it at^2 ok but shouldnt it be (at^2)/2

Answer 10

\[\frac{1}{2}\times 2a\times (t - 2)^2\]

Answer 11

initial velocity is not u C),D) is rite

Answer 12

Initial velocity must be U!

Answer 13

its not..my sir explained but i frgt

Answer 14

pls expand once aand see what u get

Answer 15

Okay I get what you meant

Answer 16

ahh now xplain

Answer 17

Hmm because it's (t-2)^2 not t^2 so an extra co-efficient of t is there

Answer 18

oh yeah and btw my sir took x as xfinal - xinitial

Answer 19

Okay!

Answer 20

hey explain!