Question

find the intervals on which the graph is concaving upward and downward and the inflection point for f(x)=In(x^2+6x+13

Answer 1

Can you use the equation function, please... Arigatou gozaimasu...

Answer 2

what do you mean

Answer 3

is it \[\ln(x^2+6x+13)\] ?

Answer 4

yes

Answer 5

\[(-\infty , -5)\] U \[(1,\infty)\] : concave upward
\[(-5,-1)\] : concave downward

Answer 6

points of inflection would be -5, -1

Answer 7

how did you get the -5 and -1 do you mind showing me mathematically

Answer 8

differentiate the given function twice and equate it to zero, you'll get it
after differentiating twice, we get \[(-2x^2 -12x-10)/(x^2+6x+13)^2\]
equate the numerator to 0 and you should get there