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If vector v lies in the second quadrant, makes an angle of 3pi/4 with the positive x axis and v = 6, find v in the component form
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|v| = 6 perhaps?
pi/4 is 45 degrees
6 = sqrt(2) s = 1 s = sqrt(2)/6 is the ratio of the side to hypotenuse then right?
s = 6/sqrt(2) :) had my ups and downs corssed
sorry hang on....it's 3pi/4
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|dw:1323714616322:dw|
its still a 45; only the i part is - and the j part is +
ALRIGH....lemme solve real quick...will u verify it for me?
sure, if i can remember what it is im doing ;)
okay...so i get < -6/sqrt(2), 6/sqrt(2) >
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good, and that can be simplified; to <-3sqrt(2),3sqrt(2)> right?
awesomeness...thx so much
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