Question

HELP! A simplified version of sin2 θ (1 + cot2 θ) = 1 is

Answer 1

hmm, dunno beside just distributing

Answer 2

dint see a trig sub

Answer 3

:/

Answer 4

trig sub?

Answer 5

i get just \[\sin^2\theta + cox^2 \theta\]

Answer 6

How?

Answer 7

Whats that Tyler?

Answer 8

whats the 2nd part of it

Answer 9

Oh wait actually

Answer 10

divide sin^2

Answer 11

I did \[\sin^2\theta + \sin^2\theta*\frac{\cos^2\theta}{\sin^2\theta}\]

Answer 12

sin^2 θ (csc^2 θ) ?
is that what you meant?

Answer 13

then you have 1+cos^2=1/sin^2

Answer 14

which is -sin^2=1/sin^2

Answer 15

so then you multiply sin^2 back to have -sin^4 = 1

Answer 16

ALl my answers start with sin2 θ

Answer 17

Then you get sin^2 + cos^2 which is 1

Answer 18

sin^2 θ (1 + cot^2 θ) = 1
sin^2 θ + cos^2 θ = 1

Answer 19

:(

Answer 20

??

Answer 21

\[Answer = \sin^2\theta + \cos^2 \theta\]