Question

Simplify:

Answer 1

simplify what?

Answer 2

simplified

Answer 3

\[2x-2y \over 3x+3y \]
.
\[6x+6y \over x ^{2}-y ^{2}\]

Answer 4

Answer choices are:
A. 4
B. \[2 \over 3(x-y)\]
C. \[4 \over x+y\]

Answer 5

I put the . there to show its times because I don't know how to put the dot in between the problems

Answer 6

Yes that is the problem

Answer 7

\[\frac{2x-2y}{3x+3y}\times \frac{6x+6y}{x^2-y^2}\]

Answer 8

\[\frac{4}{x+y}\]

Answer 9

lot of factoring and canceling for this one
you need the steps?

Answer 10

Yes please! (:

Answer 11

actually factors as this
\[\frac{2(x-y)6(x+y)}{3(x+y)(x+y)(x-y)}\]

Answer 12

What do I have to do to factor it? I'm confused.

Answer 13

\[2x-2y=2(x-y)\]

Answer 14

\[6x+6y=6(x+y)\]

Answer 15

\[3x+3y=3(x+y)\]

Answer 16

\[x^2-y^2=(x+y)(x-y)\]

Answer 17

so you factor as much as you can to see what factors you might have in common in the numerator and denominator. then you cancel each factor you have in common to reduce the fraction

Answer 18

Alright thanks! (:

Answer 19

when you get this
\[\frac{2(x-y)6(x+y)}{3(x+y)(x+y)(x-y)}\] then you get rid of all common factors

Answer 20

\[\frac{2\cancel{(x-y)}6(x+y)}{3(x+y)(x+y)\cancel{(x-y)}}\]

Answer 21

\[\frac{12(x+y)}{3(x+y)(x+y)}\]

Answer 22

\[\frac{12\cancel{(x+y)}}{3\cancel{(x+y)}(x+y)}\]

Answer 23

so finally you get
\[\frac{4}{x+y}\]

Answer 24

Exactly what I was thinking!! (: Thank you very much!!

Answer 25

yw